Find the area of given Circle
9 in
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Find the Area & Perimeter of Square, Rectangle, Triangle, Circle & More
Name
Grade
School
Date
Questions20
Score
1
2
Find the area of given Square
8 in8 in8 in8 in
3
Find the area of given Right Triangle
9 in8 in
4
Find the area of given Rectangle
8 in2 in8 in2 in
5
Find the area of given Right Triangle
8 in3 in
6
Find the area of given Rectangle
9 in8 in9 in8 in
7
Find the area of given Circle
8 in
8
Find the area of given Square
5 in5 in5 in5 in
9
Find the area of given Right Triangle
8 in2 in
10
Find the area of given Rectangle
4 in3 in4 in3 in
11
Find the perimeter of given Triangle
7 in7 in3 in
12
Find the perimeter of given Rectangle
8 in2 in8 in2 in
13
Find the perimeter of given Pentagon
6 in6 in6 in6 in6 in
14
Find the perimeter of given Circle
8 in
15
Find the perimeter of given Square
8 in8 in8 in8 in
16
Find the perimeter of given Circle
9 in
17
Find the perimeter of given Trapezoid
5 in10 in9 in4 in
18
Find the perimeter of given Rectangle
5 in2 in5 in2 in
19
Find the perimeter of given Parallelogram
4 in2 in4 in2 in
20
Find the perimeter of given Square
10 in10 in10 in10 in
Answers Key
Show All Workout
1
Find the area of given Circle
9 in
Area = 254.47 in2
Solution
Area of the circle = π x r2
Radius (r) = 9 in
Area = 3.14 x 9 x 9 ; where π = 3.14
Area = 254.47 in 2
Radius (r) = 9 in
Area = 3.14 x 9 x 9 ; where π = 3.14
Area = 254.47 in 2
2
Find the area of given Square
8 in8 in8 in8 in
Area = 64 in2
Solution
Area of the square = side2
Side = 8 in
Area = 8 x 8
Area = 64 in 2
Side = 8 in
Area = 8 x 8
Area = 64 in 2
3
Find the area of given Right Triangle
9 in8 in
Area = 36 in2
SolutionBase (b) = 8 in
Height (h) = 9 inArea =36 in 2
Area of triangle =
12
x b x h
Height (h) = 9 in
Area =
12
x 8 x 9
4
Find the area of given Rectangle
8 in2 in8 in2 in
Area = 16 in2
Solution
Area of the Rectangle = l x b
Length (l) = 8 in
Breadth (b) = 2 in
Area = 8 x 2
Area = 16 in 2
Length (l) = 8 in
Breadth (b) = 2 in
Area = 8 x 2
Area = 16 in 2
5
Find the area of given Right Triangle
8 in3 in
Area = 12 in2
SolutionBase (b) = 3 in
Height (h) = 8 inArea =12 in 2
Area of triangle =
12
x b x h
Height (h) = 8 in
Area =
12
x 3 x 8
6
Find the area of given Rectangle
9 in8 in9 in8 in
Area = 72 in2
Solution
Area of the Rectangle = l x b
Length (l) = 9 in
Breadth (b) = 8 in
Area = 9 x 8
Area = 72 in 2
Length (l) = 9 in
Breadth (b) = 8 in
Area = 9 x 8
Area = 72 in 2
7
Find the area of given Circle
8 in
Area = 201.06 in2
Solution
Area of the circle = π x r2
Radius (r) = 8 in
Area = 3.14 x 8 x 8 ; where π = 3.14
Area = 201.06 in 2
Radius (r) = 8 in
Area = 3.14 x 8 x 8 ; where π = 3.14
Area = 201.06 in 2
8
Find the area of given Square
5 in5 in5 in5 in
Area = 25 in2
Solution
Area of the square = side2
Side = 5 in
Area = 5 x 5
Area = 25 in 2
Side = 5 in
Area = 5 x 5
Area = 25 in 2
9
Find the area of given Right Triangle
8 in2 in
Area = 8 in2
SolutionBase (b) = 2 in
Height (h) = 8 inArea =8 in 2
Area of triangle =
12
x b x h
Height (h) = 8 in
Area =
12
x 2 x 8
10
Find the area of given Rectangle
4 in3 in4 in3 in
Area = 12 in2
Solution
Area of the Rectangle = l x b
Length (l) = 4 in
Breadth (b) = 3 in
Area = 4 x 3
Area = 12 in 2
Length (l) = 4 in
Breadth (b) = 3 in
Area = 4 x 3
Area = 12 in 2
11
Find the perimeter of given Triangle
7 in7 in3 in
Perimeter = 17 in
Solution
Perimeter of the shape = Sum of the measure of all the sides
side 1 = 7 in
side 2 = 7 in
side 3 = 3 in
Perimeter = 7 + 7 + 3
∴ Perimeter = 17 in
side 1 = 7 in
side 2 = 7 in
side 3 = 3 in
Perimeter = 7 + 7 + 3
∴ Perimeter = 17 in
12
Find the perimeter of given Rectangle
8 in2 in8 in2 in
Perimeter = 20 in
Solution
Perimeter of a Rectangle = 2(l+b)
Length (l) = 8 in
Breadth (b) = 2 in
Perimeter = 2 x (8 + 2)
∴ Perimeter = 20 in
Length (l) = 8 in
Breadth (b) = 2 in
Perimeter = 2 x (8 + 2)
∴ Perimeter = 20 in
13
Find the perimeter of given Pentagon
6 in6 in6 in6 in6 in
Perimeter = 30 in
Solution
Perimeter of the shape = Sum of the measure of all the sides
Side = 6 in
Perimeter = 6 + 6 + 6 + 6 + 6
∴ Perimeter = 30 in
Side = 6 in
Perimeter = 6 + 6 + 6 + 6 + 6
∴ Perimeter = 30 in
14
Find the perimeter of given Circle
8 in
Perimeter = 50.27 in
Solution
Perimeter of a circle = 2 x π x r
Radius (r) = 8 in
Perimeter = 2 x 3.14 x 8 ; where π = 3.14
∴ Perimeter = 50.27 in
Radius (r) = 8 in
Perimeter = 2 x 3.14 x 8 ; where π = 3.14
∴ Perimeter = 50.27 in
15
Find the perimeter of given Square
8 in8 in8 in8 in
Perimeter = 32 in
Solution
Perimeter of a square = 4 x side
side = 8 in
Perimeter = 4 x 8
∴ Perimeter = 32 in
side = 8 in
Perimeter = 4 x 8
∴ Perimeter = 32 in
16
Find the perimeter of given Circle
9 in
Perimeter = 56.55 in
Solution
Perimeter of a circle = 2 x π x r
Radius (r) = 9 in
Perimeter = 2 x 3.14 x 9 ; where π = 3.14
∴ Perimeter = 56.55 in
Radius (r) = 9 in
Perimeter = 2 x 3.14 x 9 ; where π = 3.14
∴ Perimeter = 56.55 in
17
Find the perimeter of given Trapezoid
5 in10 in9 in4 in
Perimeter = 28 in
Solution
Perimeter of the shape = Sum of the measure of all the sides
side 1 = 5 in
side 2 = 10 in
side 3 = 9 in
side 4 = 4 in
Perimeter = 5 + 10 + 9 + 4
∴ Perimeter = 28 in
side 1 = 5 in
side 2 = 10 in
side 3 = 9 in
side 4 = 4 in
Perimeter = 5 + 10 + 9 + 4
∴ Perimeter = 28 in
18
Find the perimeter of given Rectangle
5 in2 in5 in2 in
Perimeter = 14 in
Solution
Perimeter of a Rectangle = 2(l+b)
Length (l) = 5 in
Breadth (b) = 2 in
Perimeter = 2 x (5 + 2)
∴ Perimeter = 14 in
Length (l) = 5 in
Breadth (b) = 2 in
Perimeter = 2 x (5 + 2)
∴ Perimeter = 14 in
19
Find the perimeter of given Parallelogram
4 in2 in4 in2 in
Perimeter = 12 in
Solution
Perimeter of the shape = Sum of the measure of all the sides
side 1 = 4 in
side 2 = 2 in
side 3 = 4 in
side 4 = 2 in
Perimeter = 4 + 2 + 4 + 2
∴ Perimeter = 12 in
side 1 = 4 in
side 2 = 2 in
side 3 = 4 in
side 4 = 2 in
Perimeter = 4 + 2 + 4 + 2
∴ Perimeter = 12 in
20
Find the perimeter of given Square
10 in10 in10 in10 in
Perimeter = 40 in
Solution
Perimeter of a square = 4 x side
side = 10 in
Perimeter = 4 x 10
∴ Perimeter = 40 in
side = 10 in
Perimeter = 4 x 10
∴ Perimeter = 40 in
Find the Area & Perimeter of 2D Shapes Worksheet
Find the area & perimeter of 2d shapes (square, rectangle, triangle, circle & more) worksheet with answers for 6th grade math curriculum is available online for free in printable and downloadable (pdf & image) format. Tap on PRINT, PDF or IMAGE button to print or download this grade-6 geometry worksheet to practice how to find the area and perimeter of 2-dimensional shapes such as square, rectangle, right angle triangle, circle, parallelogram, trapezoid, rhombus and pentagon.
How to Use this Worksheet
In this sixth grade 2d geometry worksheet, students are required to find the area and perimeter of 2d-shapes such as circle, right angle triangle, rectangle, square, trapezoid, pentagon and rhombus by applying the appropriate input values in corresponding formulas.
The below is formulas to find the area of
Square = side x side
Rectangle = length x width
Triangle = 1/2 x base x height
Circle = π r2
The below is formulas to find the perimeter of
Square = 4 x side
Rectangle = 2 x (length + width)
Triangle = side 1 + side 2 + side 3
Circle = 2 π r
Trapezoid = side 1 + side 2 + side 3 + side 4
Parallelogram = side 1 + side 2 + side 3 + side 4
Pentagon = 5 x side
Teachers, tutors, parents or students can check or validate the solved questions by using the corresponding answers key which comprises the step by step work on how to find the area and perimeter of square, rectangle, triangle, circle, parallelogram, trapezoid, rhombus and pentagon.
Generate More Worksheets displayStudents, teachers, tutors or parents can generate unlimited set of questions and answers by using this "NEW WORKSHEET" button to prepare exam, assignments, classwork or homework problems, or step by step calculation on finding area and perimeter of square, rectangle, triangle, circle, parallelogram, trapezoid, rhombus and pentagon.
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